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Atrisini vienādojumu log22 (2x) + log2 = 23








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( 1 + log2x)2 + 2 - log2x - 23 = 0
log2x = t
t2 + 2t + 1 + 2 - t -23 = 0
t2 + t - 20 = 0
t1 = 4;          t2 = -5
log2x = 4;   log2x = -5
x1 = 16;      x2 =

2011-05-23 22:52

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